Bài 1 trang 160 SGK Toán 5

Tính:

a) \(\dfrac{2}{3}+ \dfrac{3}{5}\);               \(\dfrac{7}{12}-\dfrac{2}{7}+\dfrac{1}{12}\) ;             \(\dfrac{12}{17}-\dfrac{5}{17}-\dfrac{4}{17}\).

b) \(578,69 + 281,78 \);                        \(594,72 + 406,38 - 329,47\).

Lời giải

a) +) \(\dfrac{2}{3}+ \dfrac{3}{5}  = \dfrac{10}{15} + \dfrac{9}{15}= \dfrac{19}{15}\);

    +) \(\dfrac{7}{12}- \dfrac{2}{7}+ \dfrac{1}{12} = \dfrac{49}{84} - \dfrac{24}{84} + \dfrac{7}{84}\)

      \(= \dfrac{25}{84}+ \dfrac{7}{84} = \dfrac{32}{84} = \dfrac{8}{21}\);

    +) \(\dfrac{12}{17}- \dfrac{5}{17} - \dfrac{4}{17}= \dfrac{7}{17} - \dfrac{4}{17} = \dfrac{3}{17}\).

b) +) \(578,69 + 281,78 = 860,47\); 

    +) \(594,72 + 406,38 - 329,47 \) \(= 1001,1 - 329,47 = 671,63\).


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