a) \((2x - 3) - (x - 5) = (x + 2) - (x - 1)\)
\(2x - 3 - x + 5 = x +2 - x +1\)
\(x +2 =3\)
\(x = 3 - 2\)
\(x = 1\)
Vậy \(x = 1\)
b) \(2(x - 1) - 5(x + 2) = -10\)
\(2x - 2 - 5x -10 = -10\)
\(2x - 5x = -10 + 10 + 2\)
\(-3x = 2\)
\( x =\dfrac{{ - 2}}{3}\)
Vậy \(x = \dfrac{{ - 2}}{3}\)
