Bài 12 trang 7 SBT toán 8 tập 1

Đề bài

Tính:

\(a)\) \({\left( {x - 1} \right)^2}\)

\(b)\) \({\left( {3 - y} \right)^2}\)

\(c)\) \({\left( {x - \dfrac{1}{2}} \right)^2}\)

Lời giải

\(a)\) \({\left( {x - 1} \right)^2}= {x^2} - 2x + 1\)

\(b)\) \({\left( {3 - y} \right)^2}=3^2-2.3.y+y^2\)\(= 9 - 6y + {y^2}\)

\(c)\) \({\left( {x - \dfrac{1}{2}} \right)^2} =x^2-2.x.\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2\)\(= {x^2} - x + \dfrac{1}{4}\)


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