Ta có: \(A = \left\{ {...,-5,-3,-1,1,3,5....} \right\}\)
Suy ra: \(A = \left\{ {2k - 1|k \in \mathbb{Z}} \right\}\)
\(B = \left\{ {...,-9,-6,-3,0,3,6,9....} \right\}\)
Suy ra \(B = \left\{ {3k|k \in \mathbb{Z}} \right\}\)
Vậy suy ra: \({\rm{A}} \cap B = {\rm{\{ }}3(2k - 1)|k \in Z{\rm{\} }}\)
