Ta thấy, \({Q_{\left( {O,0} \right)}}\left( A \right) = A,\) \({Q_{\left( {O,0} \right)}}\left( B \right) = B,\) \({Q_{\left( {O,0} \right)}}\left( C \right) = C,\) \({Q_{\left( {O,0} \right)}}\left( D \right) = D\)
Nên \({Q_{\left( {O,0} \right)}}\left( {ABCD} \right) = ABCD\).
\({Q_{\left( {O,\pi } \right)}}\left( A \right) = C,\) \({Q_{\left( {O,\pi } \right)}}\left( B \right) = D,\) \({Q_{\left( {O,\pi } \right)}}\left( C \right) = A,\) \({Q_{\left( {O,\pi } \right)}}\left( D \right) = B\)
Nên \({Q_{\left( {O,0} \right)}}\left( {ABCD} \right) = CDAB\).
Vậy có \(2\) phép quay cần tìm.
Chọn B.