a)
\({n_{Fe}} = \dfrac{{{m_{Fe}}}}{{{M_{Fe}}}} = \dfrac{{28}}{{56}} = 0,5\,mol\)
\({n_{Cu}} = \dfrac{{{m_{Cu}}}}{{{M_{Cu}}}} = \dfrac{{64}}{{64}} = 1\,mol\)
\({n_{Al}} = \dfrac{{{m_{Al}}}}{{{M_{Al}}}} = \dfrac{{5,4}}{{27}} = 0,2\,mol\)
b)
\({V_{C{O_2}}} = {n_{C{O_2}}}.22,4 = 0,175.22,4 = 3,92\,(l)\)
\({V_{{H_2}}} = {n_{{H_2}}}.22,4 = 1,25.22,4 = 28\,(l)\)
\({V_{{N_2}}} = {n_{{N_2}}}.22,4 = 3.22,4 = 67,2\,(l)\)
c)
\(\begin{gathered} {n_{C{O_2}}} = \dfrac{{{m_{C{O_2}}}}}{{{M_{C{O_2}}}}} = \dfrac{{0,44}}{{44}} = 0,01\,mol \hfill \\ {n_{{H_2}}} = \dfrac{{{m_{{H_2}}}}}{{{M_{{H_2}}}}} = \dfrac{{0,04}}{2} = 0,02\,mol \hfill \\ {n_{{N_2}}} = \dfrac{{{m_{{N_2}}}}}{{{M_{{N_2}}}}} = \dfrac{{0,56}}{{28}} = 0,02\,mol \hfill \\ \to {n_{hh}} = {n_{C{O_2}}} + {n_{{H_2}}} + {n_{{N_2}}}\;\;\;\;\;\;\;\;\;\;\;\hfill\\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;= 0,01 + 0,02 + 0,02 = 0,05\,mol \hfill \\ \to {V_{hh}} = {n_{hh}}.22,4 = 0,05.22,4 = 1,12\,(l) \hfill \\ \end{gathered} \)
