Bài 36 trang 11 SBT toán 6 tập 2

Rút gọn:\(A = \dfrac{{4116 - 14}}{{10290 - 35}}\);               \(B = \dfrac{{2929 - 101}}{{2.1919 + 404}}\)

Lời giải

\(\eqalign{
& {\rm{A}} = {{4116 - 14} \over {10290 - 35}} \cr 
& \,\,\,\,\,\, = {{14.294 - 14} \over {35.294 - 35}} \cr 
& \,\,\,\,\,\, = {{14.(294 - 1)} \over {35.(294 - 1)}} \cr 
& \,\,\,\,\,\, = {{14} \over {35}}\, = {{2.7} \over {5.7}} = {2 \over 5} \cr} \)

\(\eqalign{
& B = {{2929 - 101} \over {2.1919 + 404}} \cr 
& \,\,\,\,\, = {{101.29 - 101} \over {2.101.19 + 2.2.101}} \cr 
& \,\,\,\,\, = {{101.(29 - 1)} \over {2.101.(19 + 2)}} \cr 
& \,\,\,\,\, = {{(29 - 1)} \over {2.(19 + 2)}} = {{28} \over {2.21}} \cr 
& \,\,\,\,\, = {{2.2.7} \over {2.3.7}} = {2 \over 3} \cr} \)


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