Bài 39 trang 14 SBT toán 7 tập 1

Tính: \(\displaystyle {\left( { - {1 \over 2}} \right)^0};{\left( {3{1 \over 2}} \right)^2};{\left( {2,5} \right)^3};{\left( { - 1{1 \over 4}} \right)^4}\)

Lời giải

\(\displaystyle {\left( { - {1 \over 2}} \right)^0} = 1;\)

\(\displaystyle {\left( {3{1 \over 2}} \right)^2} = {\left( {{7 \over 2}} \right)^2} = {{49} \over 4} = 12{1 \over 4}\) ;

\(\displaystyle {\left( {2,5} \right)^3} = 15,625;\)

\(\displaystyle {\left( { - 1{1 \over 4}} \right)^4} = \left( {{{ - 5} \over 4}} \right)^4 = {{625} \over {256}} = 2{{113} \over {256}}\).


Quote Of The Day

“Two things are infinite: the universe and human stupidity; and I'm not sure about the universe.”