a) Ta có: \(8\dfrac{2}{3}:4\dfrac{1}{3} - 50 = \dfrac{{26}}{3}:\dfrac{{13}}{3} - 50\)\( = 2 - 50 = - 48\)
Mà \( - 48 < - 47\) nên \(8\dfrac{2}{3}:4\dfrac{1}{3} - 50 < - 47.\)
b) Ta có \(6 = \sqrt {36} < \sqrt {37} \)
Mà \(\sqrt {14} < \sqrt {15} \) \( \Rightarrow \sqrt {37} - \sqrt {14} > \sqrt {37} - \sqrt {15} \)\(> 6 - \sqrt {15} \) (do \(\sqrt {37} > 6\))
Vậy \(\sqrt {37} - \sqrt {14} > 6 - \sqrt {15} .\)
