Bài 4 trang 149 SGK Toán 5

Điền dấu >, <, =  vào chỗ chấm:

\(\dfrac{7}{12}....\dfrac{5}{12}\)                   \(\dfrac{2}{5}.....\dfrac{6}{15}\)                  \(\dfrac{7}{10}....\dfrac{7}{9}\).

+) \(\dfrac{7}{12}  > \dfrac{5}{12}\) (vì \(7>5\)).

+) Ta có: \(\dfrac{2}{5}= \dfrac{2 \times 3}{5 \times 3} = \dfrac{6}{15}\) 

     Vậy \(\dfrac{2}{5} = \dfrac{6}{15}\).

+) \(\dfrac{7}{10} < \dfrac{7}{9}\) (vì \(10>9\)).