Bài 4 trang 9 SGK Toán 5

Điền dấu >, <, = vào chỗ chấm:

\( \dfrac{7}{10}\) ... \(\dfrac{9}{10}\)                            \(\dfrac{92}{100}\) ... \(\dfrac{87}{100}\);

\(\dfrac{5}{10}\) ... \(\dfrac{50}{100}\)                          \(\dfrac{8}{10}\) ... \(\dfrac{29}{100}\).

Lời giải

+) \( \dfrac{7}{10}\) \(<\dfrac{9}{10}\) ;             

+) \(\dfrac{92}{100}\) \(>\dfrac{87}{100}\);            

+) \(\dfrac{5}{10}= \dfrac{5 \times 10}{10 \times }=\dfrac{50}{100}\);   

    Vậy: \(\dfrac{5}{10}=\dfrac{50}{100}\);        

+)  \(\dfrac{8}{10} = \dfrac{8 \times 10}{10\times 10}=\dfrac{80}{100}\)

   Vì \(80 < 29\) nên \(\dfrac{80}{100}>\dfrac{29}{100}\). 

   Vậy: \(\dfrac{8}{10}>\dfrac{29}{100}\).


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