Bài 46 trang 26 SGK Toán 7 tập 1

Đề bài

 Tìm x trong các tỉ lệ thức sau 

a) \(\dfrac{x}{27} = \dfrac{-2}{3,6}\)

b) \(-0,52 : x = -9,36: 16,38\)

c) \(\dfrac{4\dfrac{1}{4}}{2\dfrac{7}{8}} = \dfrac{x}{1,61}\)

Lời giải

a) \(\dfrac{x}{27} = \dfrac{-2}{3,6}\) 

\(\begin{array}{l}
3,6.x =  - 2.27\\
3,6.x =  - 54\\
x=-54:3,6\\  x =  - 15
\end{array}\)

b) 

\(\begin{array}{l}
 - 0,52:x =  - 9,36:16,38\\
\dfrac{{ - 0,52}}{x} = \dfrac{{ - 9,36}}{{16,38}}\\
-9,36x = (-0,52).16,38\\
-9,36x = -8,5176\\
x=(-8,5176):(-9,36)\\ x = 0,91
\end{array}\)

c) \(\dfrac{4\dfrac{1}{4}}{2\dfrac{7}{8}} = \dfrac{x}{1,61}\)

\(\begin{array}{l} \dfrac{{\dfrac{{17}}{4}}}{{\dfrac{{23}}{8}}} = \dfrac{x}{{1,61}}\\ \dfrac{{17}}{4}.\dfrac{8}{{23}} = \dfrac{x}{{1,61}}\\ \dfrac{{34}}{{23}} = \dfrac{x}{{1,61}}\\23x=34.1,61\\ 23x = 54,74\\x=54,74:23\\ x = 2,38 \end{array}\)


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