Vậy:(\left( {6{x^2} + 13x - 5} \right):\left( {2x + 5} \right)\)\(=3x-1\)
Vậy \(\left( {{x^3} - 3{x^2} + x - 3} \right):\left( {x - 3} \right)\)\(=x^2+1\)
Vậy \(\left( {2{x^4} + {x^3} - 5{x^2} - 3x - 3} \right):\left( {{x^2} - 3}\right)\)\(=2x^2+x+1\)
