\({n_{{O_2}}} = \frac{{{m_{{O_2}}}}}{{{M_{{O_2}}}}} = \frac{{100}}{{32}} = 3,125\,mol\)\( \to {V_{{O_2}}} = {n_{{O_2}}}.24 = 3,125.24 = 75\,(l)\)
\({n_{C{O_2}}} = \frac{{{m_{C{O_2}}}}}{{{M_{C{O_2}}}}} = \frac{{100}}{{44}} = \frac{{25}}{{11}}\,mol\)\( \to {V_{C{O_2}}} = {n_{C{O_2}}}.24 = \frac{{25}}{{11}}.24 = \frac{{600}}{{11}}\,(l)\)
\( \to {V_{hh}} = {V_{{O_2}}} + {V_{C{O_2}}}\)\( = 75 + \frac{{600}}{{11}} = \frac{{1425}}{{11}}\,(l) \approx 129,55(l)\)