a) \(\displaystyle {\rm{}}{3 \over 4}x = 1 \Rightarrow x = 1:{3 \over 4} = 1.{4 \over 3} = {4 \over 3}\)
b) \(\displaystyle {4 \over 7}x = {9 \over 8} - 0,125 \)
\(\displaystyle {4 \over 7}x = {9 \over 8} - {1 \over 8} = 1 \)
\(\displaystyle x = 1:{4 \over 7} = 1.{7 \over 4} = {7 \over 4}.\)
