Bài 1. Tính : \({3^2}.7 - ({1^{10}} + 24{\rm{ }}):{5^2}\)
Bài 2. Tìm \(x ∈\mathbb N\), biết :
a) \((17x – 25 ) : 8 + 65 =9^2\) ;
b) \(2010^5(x – 60 ) =2010^6\).
Bài 1. \(3^7.7–(1.10 + 24 ):5^2=9.7 – 25 :25\)\(\, = 63 – 1 =62.\)
Bài 2.
a) \((17x -25 ): 8 =81 – 65\)
\(17x – 25 =16 . 8\)
\( 17x =128 +25\)
\( 17 x = 153\)
\( x =9\)
b) \(x - 60 = 2010^6 : 2010^5\)
\(x- 60 = 2010\)
\(x =2010 + 60 =2070.\)