\(6C{O_2} + 12{H_2}O\buildrel {Ánh\,sáng\,mặt\,trời} \over
\longrightarrow {C_6}{H_{12}}{O_6} + 6{O_2} + 6{H_2}O\)
\({{{{6.15.10}^3}} \over {180}}\) mol \({{{{15.10}^6}} \over {180}}\) mol
\({m_{{O_2}}} = {{{{15.10}^6}.15} \over {180}}.32 = {16.10^6} = 16\) tấn
\({m_{C{O_2}}} = {{{{15.10}^6}.15} \over {180}}.44 = {22.10^6} = 22\) tấn.
