\(a)\,\,{\left[ {{{\left( {\dfrac{{ - 3}}{4}} \right)}^3}} \right]^2} = {\left( {\dfrac{{ - 3}}{4}} \right)^{3.2}} \)\(\,= {\left( {\dfrac{{ - 3}}{4}} \right)^6}\)
Do đó:
\(b)\;{\left( {0,1} \right)^8} = {\left( {0,1} \right)^{4.2}} = \,\,{\left[ {{{\left( {0,1} \right)}^4}} \right]^2}\)
