\( \displaystyle 2\dfrac{3}{5} = {{2 \times 5 + 3} \over 5} =\dfrac{13}{5}\) ;
\( \displaystyle 5\dfrac{4}{9} = {{5 \times 9 + 4} \over 9} =\dfrac{49}{9}\) ;
\( \displaystyle 9\dfrac{3}{8}= {{9 \times 8 + 3} \over 8} =\dfrac{75}{8}\) ;
\( \displaystyle 12\dfrac{7}{10} = {{12 \times 10 + 7} \over {10}} =\dfrac{127}{10}\) .
