a.
\(\eqalign{ & y' = 2\tan 3x.3\left( {1 + {{\tan }^2}3x} \right) + 6x\left( {1 + {{\cot }^2}3{x^2}} \right) \cr & \Rightarrow dy = y'dx = \left[ {6\tan 3x\left( {1 + {{\tan }^2}3x} \right) + 6x\left( {1 + {{\cot }^2}3{x^2}} \right)} \right]dx \cr} \)
b.
\(\eqalign{ & y' = {{2\cos 2x.\left( { - 2\sin 2x} \right)} \over {2\sqrt {{{\cos }^2}2x + 1} }} = {{ - \sin 4x} \over {\sqrt {{{\cos }^2}2x + 1} }} \cr & \Rightarrow dy = y'dx = - {{\sin4 x} \over {\sqrt {{{\cos }^2}2x + 1} }}dx \cr} \)
