Ta có: \({\sin}^4 x-{\cos}^4 x=0\)
\(\Leftrightarrow ({\sin}^2 x-{\cos}^2 x)({\sin}^2 x+{\cos}^2 x)=0\)
\(\Leftrightarrow-\cos 2x=0\)
\(\Leftrightarrow\cos 2x=0\)
\(\Leftrightarrow 2x=\dfrac{\pi}{2}+k\pi,k\in\mathbb{Z}\)
\(\Leftrightarrow x=\dfrac{\pi}{4}+k\dfrac{\pi}{2},k\in\mathbb{Z}\)
Đáp án: C.