Ta có: \(\text{(*)}\Leftrightarrow \dfrac{\sqrt{3}}{2}\cos x+\dfrac{1}{2}\sin x=1\)
\(\Leftrightarrow \cos {\left({x-\dfrac{\pi}{6}}\right)}=1\)
\(\Leftrightarrow x-\dfrac{\pi}{6}=k2\pi,k\in\mathbb{Z}\)
\(\Leftrightarrow x=\dfrac{\pi}{6}+k2\pi,k\in\mathbb{Z}\)
Đáp án: C.