Ta có:
\(S = \dfrac{{{u_1}}}{{1 - q}}\) \( \Leftrightarrow 3 = \dfrac{{{u_1}}}{{1 - \dfrac{2}{3}}}\) \( \Leftrightarrow {u_1} = 3\left( {1 - \dfrac{2}{3}} \right) = 3.\dfrac{1}{3} = 1\) \( \Rightarrow {u_n} = {u_1}{q^{n - 1}} = {\left( {\dfrac{2}{3}} \right)^{n - 1}}\)
