Bài 3.6 trang 57 SBT đại số 10

\(\left\{ {\begin{array}{*{20}{c}}{3x + 2 > 0}\\{x \ne 0}\\{2 - x \ge 0}\end{array}} \right.\)\( \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}{x >  - \dfrac{2}{3}}\\{x \ne 0}\\{x \le 2}\end{array}} \right.\)\( \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}{ - \dfrac{2}{3} < x \le 2}\\{x \ne 0}\end{array}} \right.\)

Đáp án D.