Bài 56 trang 12 SBT toán 6 tập 1

Đề bài

Tính nhanh: 

\(a)\) \(2.31.12+4.6.42+8.27.3\)

\(b)\) \(36.28+36.82+64.69+64.41\)

Lời giải

\(a)\) \(2.31.12+4.6.42+8.27.3\)

    \(=24.31+24.42+24.27\)

    \(= 24.(31+42+27) \)

    \(= 24 . 100 = 2400\)

\(b)\) \(36.28+36.82+64.69+64.41 \)

    \(= 36.(28+82) + 64.(69+41)\)

    \(= 36.110 + 64.110\)

    \(= 110.(36+64) \)

    \(= 110 . 100 = 11000\)


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