Bài 86 trang 43 SGK Toán 6 tập 2

Tìm x, biết: 

a) \(\dfrac{4}{5}.x=\dfrac{4}{7};\)               b) \(\dfrac{3}{4}:x=\dfrac{1}{2}\).

a)  Từ \(\dfrac{4}{5}.x=\dfrac{4}{7}\) suy ra  \(x=\dfrac{4}{7}:\dfrac{4}{5}=\dfrac{4}{7}.\dfrac{5}{4}=\dfrac{5}{7}\) ;

b) Từ \(\dfrac{3}{4}:x=\dfrac{1}{2}\) suy ra  \(x=\dfrac{3}{4}:\dfrac{1}{2}=\dfrac{3}{4}.\dfrac{2}{1}=\dfrac{3}{2}.\)