Trả lời câu hỏi Bài 10 trang 35 Toán 6 Tập 2

\(\eqalign{& a)\,\,{3 \over 4}.{5 \over 7} = ... = ...;  \cr & b)\,\,{3 \over {10}}.{{25} \over {42}} = {{3.25} \over {10.42}} = {{1.5} \over {2.14}} = ... \cr} \)

Lời giải

\(\eqalign{& a)\,\,{3 \over 4}.{5 \over 7} = {{3.5} \over {4.7}} = {{15} \over {28}}  \cr & b)\,\,{3 \over {10}}.{{25} \over {42}} = {{3.25} \over {10.42}} = {{1.5} \over {2.14}} = {5 \over {28}} \cr} \)


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