Bài 1 trang 5 SGK Toán 8 tập 1

Làm tính nhân:

a) \({x^2}\left( {5{x^3} - x - \dfrac{1}{2}} \right)\);

b) \((3xy-{x^2} + y)\dfrac{2}{3}{x^2}y\);

c) \((4{x^3} - 5xy + 2x)\left( { - \dfrac{1}{2}xy} \right)\).

Lời giải

\(\eqalign{
& a)\,\,{x^2}\left( {5{x^3} - x - {1 \over 2}} \right) \cr
& = {x^2}.5{x^3} + {x^2}.\left( { - x} \right) + {x^2}.\left( { - {1 \over 2}} \right) \cr
& = 5{x^5} - {x^3} - {1 \over 2}{x^2} \cr} \)


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