\(a)\) \(40 =8.5= {2^3}.5\)
\(60 =6.10=2.3.2.5= {2^2}.3.5\)
\(ƯCLN(40; 60) = {2^2}.5 =20\)
\(b)\) \(36 =6.6=2.3.2.3= {2^2}{.3^2}\)
\(60 =6.10=2.3.2.5= {2^2}.3.5\)
\(72 =8.9= {2^3}{.3^2}\)
\(ƯCLN(36; 60; 72) = {2^2}.3 = 12\)
\(c)\) \(13\) là số nguyên tố nên \(ƯCLN(13; 20) = 1\)
\(d)\) \(28 =4.7= {2^2}.7\)
\(39 = 3.13\)
\(35 = 5.7\)
\(ƯCLN(28 ;39 ;35)=1\)