Trả lời câu hỏi 2 Bài 2 trang 9 SGK Toán 7 Tập 1

Tìm \(x\), biết:\(\eqalign{
& a)\,\,x - {1 \over 2} = - {2 \over 3} \cr
& b)\,\,{2 \over 7} - x = - {3 \over 4} \cr} \)

Lời giải

\(\eqalign{
& a)\,\,x - {1 \over 2} = - {2 \over 3} \cr
& \,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\,\, = - {2 \over 3} + {1 \over 2} \cr
& \,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\,\, = {{ - 4} \over 6} + {3 \over 6} \cr
& \,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\,\, = {{ - 1} \over 6} \cr
& b\,)\,\,{2 \over 7} - x = - {3 \over 4} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = {2 \over 7} - \left( { - {3 \over 4}} \right) \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = {2 \over 7} + {3 \over 4} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = {8 \over {28}} + {{21} \over {28}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = {{29} \over {28}} \cr} \)


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