Trả lời câu hỏi 2 Bài 17 trang 55 SGK Toán 6 Tập 1

Tìm ƯCLN(8, 9); ƯCLN(8, 12, 15); ƯCLN(24, 16, 8).

Lời giải

Ta có: \(Ư(8) = \{ 1;2;4;8\}\)

\(Ư(9) = \{ 1;3;9\}\)

\(Ư(12) = \{ 1;2;3;4;6;12\}\)

\(Ư(15) = \{ 1;3;5;15\}\)

\(Ư(24) = \{ 1;2;3;4;6;8;12;24\}\)

\(Ư(16) = \{ 1;2;4;8;16\}\)

Suy ra \(ƯC(8,9) =\{ 1\}\) nên \(ƯCLN(8,9) = 1\) 

\(ƯC(8,12,15) = \{1\}\) nên \(ƯCLN(8,12,15) = 1\)

\(ƯC( 24,16,8) = \{ 1;2;4;8\}\) nên \(ƯCLN(24,16,8) = 8\)


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